Q. A cricket ball of mass $250\ g$ collides with a bat with velocity $10\ m/s$ and returns with the same velocity within $0.01\ second$ . The force acted on bat is
A) $25\ N$
B) $50\ N$
C) $250\ N$
D) $500\ N$
Explanation
(d) Force $= m\left( \frac{dv}{dt} \right) = \frac{0.25 \times \lbrack(10) - ( - 10)\rbrack}{0.01} = 25 \times 20 = 500\ N$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.