(a) [image:5_image243.wmf] $f = \mu R \Rightarrow F\cos{60{^\circ}} = \mu\left( W + F\sin{60{^\circ}} \right)$ Substituting $\mu = \frac{1}{2\sqrt{3}}\ \&\ W = 10\sqrt{3}$ We get $F = 20\ N$
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