Q. A plumb line is suspended from a ceiling of a car moving with horizontal acceleration of $a$. What will be the angle of inclination with vertical
A) $\tan^{- 1}{(a/g)}$
B) $\tan^{- 1}{(g/a)}$
C) $\cos^{- 1}{(a/g)}$
D) $\cos^{- 1}{(g/a)}$
Explanation
(a) $T\cos{\theta = mg}$
$T\sin\theta = ma$
$\tan\theta = \frac{a}{g}$
[image:5_image246.emf]
$\therefore\theta = \tan^{- 1}{(a/g)}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.