Q.
A block is kept on a frictionless inclined surface with angle of inclination$\ \alpha$. The incline is given an acceleration $a$ to keep the block stationary. Then $a$ is equal to
A) $g/\tan\alpha$
B) $g\ cosec\ \alpha$
C) $g$
D) $g\tan\alpha$
Explanation
(d) In the frame of wedge, the force diagram of block is shown in figure. From free body diagram of wedge,
[image:5_image254.jpeg]
For block remain stationary,
$ma\cos{\alpha = mg\sin\alpha}$
$a = g\tan\alpha$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.