Q.
A box of mass $m$ kg is placed on the rear side of an open truck accelerating at $t\ ms^{- 2}$. The coefficient of friction between the box and the surface below it is 0.4. The net acceleration of the box with respect to the truck is zero. The value of $m$ is [Given $g = 10\ ms^{- 2}$]
A) 4 kg
B) 8 kg
C) 9.78 kg
D) It could be any value
Explanation
(d) Pseudo force on the block $= m\ \times 4$ N (backward)
Force of friction = 0.4 $\times m \times 10$ N (forward)
Equating , $m \times 4 = 0.4 \times m \times 10 = 4m\ $
Clearly the equation holds good for all values of $m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.