Q. A block of $1\ kg$ is stopped against a wall by applying a force $F$ perpendicular to the wall. If $\mu = 0.2$ then minimum value of $F$ will be
A) $980\ N$
B) $49\ N$
C) $98\ N$
D) $490\ N$
Explanation
(b) $F = \frac{W}{\mu} = \frac{1 \times 9.8}{0.2} = 49\ N$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.