A boy of mass $40\ kg$ is climbing a vertical pole at a constant speed. If the coefficient of friction between his palms and the pole is $0.8$ and $g = 10\ m/s^{2}$, the horizontal force that he is applying on the pole is

Question

Dr. Abubacker · Accepted Answer

(c) Here, $\mu = 0.8$. Let $F$ be horizontal force that the body is applying on the pole. The various forces are acting on the boy as shown in the figure
[image:5_image263.png]
Frictional force,
$f = \mu N = mg$
$N = \frac{mg}{\mu} = \frac{40 	imes 10}{0.8} = 5000N \Rightarrow F = N = 500\ N$

Q. A boy of mass $40\ kg$ is climbing a vertical pole at a constant speed. If the coefficient of friction between his palms and the pole is $0.8$ and $g = 10\ m/s^{2}$, the horizontal force that he is applying on the pole is

Explanation

Reviewed by Dr. Abubacker

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