A solid disc of mass $M$ is just held in air horizontal by throwing 40 stones per sec vertically upwards to strike the disc each with a velocity $6\ ms^{- 1}$. If the mass of each stone is 0.05 kg. What is the mass of the disc ($g = 10\ ms^{- 2}$)

Question

Dr. Abubacker · Accepted Answer

(a) Weight of the disc will be balanced by the force applied by the bullet on the disc in vertically upward direction
$F = n\ m\ v$
$= 40 	imes 0.05 	imes 6 = Mg$
$M = \frac{40 	imes 0.05 	imes 6}{16}$
$= 1.2$ kg

Q. A solid disc of mass $M$ is just held in air horizontal by throwing 40 stones per sec vertically upwards to strike the disc each with a velocity $6\ ms^{- 1}$. If the mass of each stone is 0.05 kg. What is the mass of the disc ($g = 10\ ms^{- 2}$)

Explanation

Reviewed by Dr. Abubacker

Want more practice?