System shown in figure is in equilibrium and at rest. The spring and string are massless, now the string is cut. The acceleration of mass $2\ m$ and $m$ just after the string is cut will be [image:5_image115.jpeg]

Question

Dr. Abubacker · Accepted Answer

(a) Initially under equilibrium of mass $m$
$T = mg$
Now, the string is cut. Therefore, $T = mg\ $force is decreased on mass $m$ upward and downwards on mass 2$m.$
$	herefore\ a_{m} = \frac{mg}{m} = g\ \ \ \ (downwards)$
$and\ a_{2m} = \frac{mg}{2m} = \frac{g}{2}\ (upwards)$

Q. System shown in figure is in equilibrium and at rest. The spring and string are massless, now the string is cut. The acceleration of mass $2\ m$ and $m$ just after the string is cut will be

Explanation

Reviewed by Dr. Abubacker

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