Q. If force on a rocket having exhaust velocity of $300\ m/sec$ is $2010\ N$, then rate of combustion of the fuel is
A) $0.7\ kg/s$
B) $1.4\ kg/s$
C) $0.07\ kg/s$
D) $10.7\ kg/s$
Explanation
(a) $F = u\left( \frac{dm}{dt} \right) \Rightarrow \frac{dm}{dt} = \frac{F}{u} = \frac{210}{300} = 0.7\ kg/s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.