Q. A marble block of mass $2\ kg$ lying on ice when given a velocity of $6\ m/s$ is stopped by friction in $10s$. Then the coefficient of friction is
A) $0.01$
B) $0.02$
C) $0.03$
D) $0.06$
Explanation
(d) $v = u - at \Rightarrow u - \mu gt = 0\ \therefore\ \mu = \frac{u}{gt} = \frac{6}{10 \times 10} = 0.06$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.