Q. When forces $F_{1},\ F_{2},\ F_{3}$ are acting on a particle of mass $m$ such that $F_{2}$ and $F_{3}$ are naturally perpendicular, then the particle remains stationary. If the force $F_{1}$ is now removed then the acceleration of the particle is
A) $F_{1}/m$
B) $F_{2}F_{3}/mF_{1}$
C) $(F_{2} - F_{3})/m$
D) $F_{2}/m$
Explanation
(a) Force equilibrium of system, $F_{1} = \sqrt{F_{2}^{2} + F_{3}^{2}}$ [As $\theta = 90{^\circ}$]
In the absence of force $F_{1}$, Acceleration $= \frac{Net\ Force}{Mass}$
$= \frac{\sqrt{F_{2}^{2} + F_{3}^{2}}}{m} = \frac{F_{1}}{m}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.