Q. A boy having a mass equal to $40\ kilograms$ is standing in an elevator. The force felt by the feet of the boy will be greatest when the elevator $(g = 9.8\ metres/\sec^{2}{\ )}$
A) Stands still
B) Moves downward at a constant velocity of $4\ metres/sec$
C) Accelerates downward with an acceleration equal to $4\ metres/\sec^{2}$
D) Accelerates upward with an acceleration equal to $4\ metres/\sec^{2}$
Explanation
The correct answer is Option D: Accelerates upward with an acceleration equal to $4\ metres/\sec^{2}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.