
(a) Let the tension in the wire be T . The equations of motion of the two locks are,
$T - 10 = 1\ a$
$and\ \ 20 - T = 2\ a$
Eliminating $a$ form these equations,
$T = \left( \frac{40}{3} \right)N$
$Stress,\ T = \frac{\left( \frac{40}{3} \right)}{\pi\ r^{2}}$
If the minimum radius needed to avoid breakings is $r.$
$2 \times 10^{9} = \frac{\left( \frac{40}{3} \right)}{\pi\ \ r^{2}}$
Solving this,
$r = 4.6 \times 10^{- 5}\ m$