A block $A$ of mass 7 kg is placed on a frictionless table. A thread tied to it passes over a frictionless pulley and carries a body $B$ of mass 3 kg at the other end, as in figure. The acceleration of the system is (given $g = 10\ ms^{- 2}$) [image:5_image125.jpeg]

Question

Dr. Abubacker · Accepted Answer

(b) For body $A$, $T = M_{1}a = 7a$
For body $B,M_{2}\ g - T = 3a$
$3g - 7a = 3a$
10$a = 3g$
$a = \frac{3g}{10} = \frac{3 	imes 10}{10} = 3\ ms^{- 2}$

Q. A block $A$ of mass 7 kg is placed on a frictionless table. A thread tied to it passes over a frictionless pulley and carries a body $B$ of mass 3 kg at the other end, as in figure. The acceleration of the system is (given $g = 10\ ms^{- 2}$)

Explanation

Reviewed by Dr. Abubacker

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