Q. On the horizontal surface of a truck $(\mu = 0.6)$, a block of mass $1\ kg$ is placed. If the truck is accelerating at the rate of $5m/\sec^{2}$ then frictional force on the block will be

A) $5\ N$
B) $6\ N$
C) $5.88\ N$
D) $8\ N$
Explanation

(a) $F_{l} = \mu mg = 0.6 \times 1 \times 9.8 = 5.88\ N$
Pseudo force on the block $= ma = 1 \times 5 = 5\ N$
Pseudo is less then limiting friction hence static force of friction $= 5\ N$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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