Q. A vehicle of mass $m$ is moving on a rough horizontal road with momentum $P$. If the coefficient of friction between the tyres and the road be $\mu$, then the stopping distance is
A) $\frac{P}{2\mu mg}$
B) $\frac{P^{2}}{2\mu mg}$
C) $\frac{P}{2\mu m^{2}g}$
D) $\frac{P^{2}}{2\mu m^{2}g}$
Explanation
(d) $S = \frac{u^{2}}{2\mu g} = \frac{m^{2}u^{2}}{2\mu gm^{2}} = \frac{P^{2}}{2\mu m^{2}g}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.