Observer $O_{1}$ is in a lift going upwards and $O_{2}$ is on the ground. Both apply Newton’s law, and measure normal reaction on the body

Question

Dr. Abubacker · Accepted Answer

(c) The value measured by $O_{1}$ in $N_{1} = mg$ because acceleration of body with respect to $O_{1}$ is zero
The value measured by $O_{2}$ is
$N_{2} - mg = ma_{0}$
$	herefore\ N_{2} = m(g + a_{0})$
So, $N_{1} 
eq N_{2}$

Q. Observer $O_{1}$ is in a lift going upwards and $O_{2}$ is on the ground. Both apply Newton’s law, and measure normal reaction on the body

Explanation

Reviewed by Dr. Abubacker

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