(c) For upward acceleration apparent weight $= m(g + a)$
If lift suddenly stops during upward motion then apparent weight $= m(g - a)$ because instead of acceleration, we will consider retardation
In the problem it is given that scale reading initially was $60\ kg$ and due to sudden jerk reading decreasing and finally comes back to the original mark $i.e.$ , $60\ kg$
So, we can conclude that lift was moving upward with constant speed and suddenly stops