Q.
Three forces start acting simultaneously on a particle moving with velocity v. These forces are represented in magnitude and direction by the three sides of a triangle $ABC$ (as shown). The particle will now move with velocity
A) Less than v
B) Greater than v
C) $v$ in the direction of largest force $BC$
D) v remaining unchanged
Explanation
(d) Resultant force is zero, as three forces acting on the particle can be represented in magnitude and direction by three sides of a triangle in order. Hence, by Newton’s
2nd law$\ \left( \mathbf{F} = m\frac{dv}{dt} \right),\ $particle velocity (v) will be same.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.