Q. A mass of $5\ kg$ is suspended by a rope of length $2\ m$ from a ceiling. A force of $50\ N$ in the horizontal direction is applied at the mid-point of the rope. The angle made by rope with the vertical, in equilibrium is
A) $50{^\circ}$
B) $60{^\circ}$
C) $30{^\circ}$
D) $45{^\circ}$
Explanation
(d) $\tan\theta = \frac{5}{5} = 1$
[image:5_image284.emf]
$\Rightarrow \tan\theta = \tan{45{^\circ}}$
$\Rightarrow \theta = 45{^\circ}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.