Q. A small block slides without friction down an inclined plane starting from rest. Let $s_{n}$ be the distance travelled from time $t = n - 1$ to $t = n.$ Then $\frac{s_{n}}{s_{n} + 1}\ is$
A) $\frac{2n - 1}{2n}$
B) $\frac{2n + 1}{2n - 1}$
C) $\frac{2n - 1}{2n + 1}$
D) $\frac{2n}{2n + 1}$
Explanation
(c) Distance travelled in $t^{th}$ second is,
$s_{t} = u + at - \frac{1}{2}a$
$Given,\ u = 0$
$\therefore\ \ \ \frac{s_{n}}{s_{n} + 1} = \frac{an - \frac{1}{2}a}{a(n + 1) - \frac{1}{2}a} = \frac{2n - 1}{2n + 1x}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.