Q. The coefficient of static friction, $\mu_{s}$, between block $A$ of mass $2\ kg$ and the table as shown in the figure is $0.2$. What would be the maximum mass value of block $B$ so that the two blocks do not move? The string and the pulley are assumed to be smooth and massless $(g = 10\ m/s^{2})$
A) $2.0\ kg$
B) $4.0\ kg$
C) $0.2\ kg$
D) $0.4\ kg$
Explanation
(d) $\mu_{s} = \frac{m_{B}}{m_{A}} \Rightarrow 0.2 = \frac{m_{B}}{2} \Rightarrow m_{B} = 0.4\ kg$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.