Q. A monkey of mass $20\ kg$ is holding a vertical rope. The rope will not break when a mass of $25\ kg$ is suspended from it but will break if the mass exceeds $25\ kg$. What is the maximum acceleration with which the monkey can climb up along the rope $(g = 10\ m/s^{2})$
A) $10\ m/s^{2}$
B) $25\ m/s^{2}$
C) $2.5\ m/s^{2}$
D) $5\ m/s^{2}$
Explanation
(c) Tension the string $= m(g + a) =$ Breaking force
$\Rightarrow 20(g + a) = 25 \times g \Rightarrow a = g/4 = 2.5\ m/s^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.