Q. A block is gently placed on a conveyor belt moving horizontally with constant speed. After 4s the velocity of the block becomes equal to the velocity of belt. If the coefficient of friction between the block and the belt is 0.2, then velocity of the conveyor belt is
A) 2 $ms^{- 1}$
B) 4$\ ms^{- 1}$
C) 6$\ ms^{- 1}$
D) 8$\ ms^{- 1}$
Explanation
(d) For block to continue motion on belt, acceleration $a = + \mu g = 0.2 \times 10 = 2\ ms^{- 2}$
$\therefore$ Velocity of belt = Velocity of block after 4 s = 2 $\times 4$
$= 8\ ms^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.