Q. Two particle of equal mass are connected to a rope $AB$ of negligible mass, such that one is at end $A$ and the other dividing the length of the rope in the ratio 1:2 from$\ B$. The rope is rotated about end $B$ in a horizontal plane. Ratio of the tension in the smaller part to the other is (ignore effect of gravity)
A) 4:3
B) 1:4
C) 1:2
D) 1:3
Explanation
(d) Let $x$ be distance from A to O, and L the total length of string. Then , ratio of moment is
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$\frac{m_{1}}{m_{2}} = \frac{(L - x)}{L} = \frac{3 - 2}{3} = \frac{1}{3}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.