Q. Two masses of 3 kg and 5 kg are suspended from the ends of an unstreachable massless cord passing over a frictionless pulley. When the masses are released, the pressure on the pulley is
A) $2\ kgf$
B) $7.5\ kgf$
C) $8\ kgf$
D) $15\ kgf$
Explanation
(b) $T = \frac{2 \times 3 \times 5}{3 + 5}\ kgf = \frac{15}{4}\ kgf$
Pressure on the pulley $= 2T = 2 \times \frac{15}{4}$ kgf = 7.5 kgf
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.