A bullet is fired from a gun. The force on the bullet is given by $F = 600 - 2 imes 10^{5}t$, where $F$ is in $newtons$ and $t$ in seconds. The force on the bullet becomes zero as soon as it leaves the barrel. What is the average impulse imparted to the bullet

Question

A bullet is fired from a gun. The force on the bullet is given by $F = 600 - 2 	imes 10^{5}t$, where $F$ is in $newtons$ and $t$ in seconds. The force on the bullet becomes zero as soon as it leaves the barrel. What is the average impulse imparted to the bullet

Dr. Abubacker · Accepted Answer

(c) $F = 600 - 2 	imes 10^{5}t = 0 \Rightarrow t = 3 	imes 10^{- 3}\ \sec$
Impulse $I = \int_{0}^{t}{F\ dt = \int_{0}^{3 	imes 10^{- 3}}{\left( 600 - 2 	imes 10^{5}t ight)dt}}$
$= \left\lbrack 600t - 10^{5}t^{2} ightbrack_{0}^{3 	imes 10^{- 3}} = 0.9\ N 	imes \sec$

Q. A bullet is fired from a gun. The force on the bullet is given by $F = 600 - 2 \times 10^{5}t$, where $F$ is in $newtons$ and $t$ in seconds. The force on the bullet becomes zero as soon as it leaves the barrel. What is the average impulse imparted to the bullet

Explanation

Reviewed by Dr. Abubacker

Want more practice?