A particle moves in the $xy$- plane under the action of a force $\mathbf{F}$ such that the components of its linear momentum $\mathbf{p}$ at any time $t$ are $p_{x} = 2\cos{\ t},\ p_{y} = 2\sin t$. The angle between $\mathbf{F}$ and $\mathbf{p}$ at time $t$ is

Question

Dr. Abubacker · Accepted Answer

(a) Given that $\overrightarrow{P} = P_{x}i + P_{y}\widehat{j} = 2\cos t\ \widehat{i} + 2\sin t\ \widehat{j}$
$	herefore\overrightarrow{F} = \frac{d\overrightarrow{p}}{dt} = - 2\sin t\widehat{i} + 2\cos t\widehat{j}$
Now, $\overrightarrow{F}.\overrightarrow{p} = 0$ $i.e$. angle between $\overrightarrow{F}$ and $\overrightarrow{P}$ is $90{^\circ}$

Q. A particle moves in the $xy$- plane under the action of a force $\mathbf{F}$ such that the components of its linear momentum $\mathbf{p}$ at any time $t$ are $p_{x} = 2\cos{\ t},\ p_{y} = 2\sin t$. The angle between $\mathbf{F}$ and $\mathbf{p}$ at time $t$ is

Explanation

Reviewed by Dr. Abubacker

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