Q.
The acceleration of the 500 g block in figure is
A) $\frac{6g}{13}$ downwards
B) $\frac{7g}{13}downwards$
C) $\frac{8g}{13}downwards$
D) $\frac{9g}{13}$ upwards
Explanation
(c) 500g$\ - T = 500a$
$T - 100g\sin{30{^\circ} - T^{''} = 100a}$
or $T - T^{''} - 50g = 100a$
[image:5_image293.emf]
Again, $T^{''} - 50g = 50a$
From Eqs. (ii) and (iii)
$T - 100g = 150a$
Adding Eqs. (i) and (iv), 400g = 650 $a$ or $a = \frac{400g}{650} = \frac{8g}{13}$
This acceleration is downwards
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.