(c) By drawing the free body diagram of point $B$
Let the tension in the section $BC$ and $BF$ are $T_{1}$ and $T_{2}$ respectively
From Lami’s theorem
$\frac{T_{1}}{\sin{120{^\circ}}} = \frac{T_{2}}{\sin{120{^\circ}}} = \frac{T}{\sin{120{^\circ}}}$
$\Rightarrow T = T_{1} = T_{2} = 10\ N$