Q. The rate of the mass of the gas emitted from rear of a rocket is initially 0.1${kgs}^{- 1}$. If the speed of the gas relative to the rocket is ${50\ \ ms}^{- 1}$ and mass of the rocket is 2 kg, then the acceleration of the rocket (in ${ms}^{- 2})\ $is

A) 5
B) 5.2
C) 2.5
D) 25
Explanation

(c) $Acceleration\ a = \frac{\mathrm{\Delta}v}{\mathrm{\Delta}t} = \frac{v}{m} \bullet \frac{\mathrm{\Delta}m}{\mathrm{\Delta}t}$
$= \frac{50}{2} \times 0.1 = 2.5\ {ms}^{- 2}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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