Q.
Two blocks of equal masses $m$ are released from the top of a smooth fixed wedge as shown in the figure. The acceleration of the centre of mass of the two blocks is
A) $g$
B) $\frac{g}{2}$
C) $\frac{3g}{4}$
D) $\frac{g}{\sqrt{2}}$
Explanation
(b) The acceleration of the centre of mass of the block,
$= \frac{g}{2}\sqrt{(\sin{\angle ABC)^{2} + (\sin{\angle ABC)^{2}}}}$
$= \frac{g}{2}\sqrt{\sin^{2}\ 30{^\circ} + \sin^{2}60{^\circ}}$
$= \frac{g}{2}\sqrt{{(0.5)}^{2} + {(0.866)}^{2}} = \frac{g}{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.