Q. If in a stationary lift, a man is standing with a bucket full of water, having a hole at its bottom. The rate of flow of water through this hole is $R_{0}$. If the lift starts to move up and down with same acceleration and then that rates of flow of water are $R_{u}$ and $R_{d}$, then
A) $R_{0} > R_{u} > R_{d}$
B) $R_{u} > R_{0} > R_{d}$
C) $R_{d} > R_{0} > R_{u}$
D) $R_{u} > R_{d} > R_{0}$
Explanation
(b) Rate of flow will be more when lift will move in upward direction with some acceleration because the net downward pull will be more and vice-versa
$F_{upward} = m(g + a)$ and $F_{downward} = m(g - a)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.