Q. A particle moves in a straight line with retardation proportional to its displacement. Its loss of KE for any displacement $x$ is proportional to
A) $x$
B) $x^{2}$
C) $x^{0}$
D) $e^{x}$
Explanation
(b) Loss of KE = force $\times$ distance $= \ (ma)x$
As $a \propto x$
$\therefore$ Loss of $KE \propto x^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.