Q. 10 L of water per second is lifted from well through 20 m and delivered with a velocity of $10ms^{- 1},$then the power of the motor is
A) 1.5 Kw
B) 2.5 Kw
C) 3.5 Kw
D) 4.5 Kw
Explanation
(b) Power ,p$= \frac{Total\ Energy}{t}\ $ = $\frac{mgh + \frac{1}{2}{mv}^{2}}{t}\ \ \ $
$\frac{10 \times 10 \times 20 + \frac{1}{2} + 10 \times 10 \times 10}{1}$
=2000+500=2500 W=2.5 KW
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.