Q. A particle of mass $M$ starting from rest undergoes uniform acceleration. If the speed acquired in time $T$ is $V$, the power delivered to the particle is
A) $\frac{MV^{2}}{T}$
B) $\frac{1}{2}\frac{MV^{2}}{T^{2}}$
C) $\frac{MV^{2}}{T^{2}}$
D) $\frac{1}{2}\frac{MV^{2}}{T}$
Explanation
The correct answer is Option D: $\frac{1}{2}\frac{MV^{2}}{T}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.