Q. A man, by working a hand pump fixed to a well, pumps out $10\ m^{3}$ water in 1 s. If the water in the well is 10 m below the ground level, then the work done by the man is $(g = 10ms^{- 2})$
A) $10^{3}$J
B) $10^{4}$J
C) $10^{5}$J
D) $10^{6}$J
Explanation
(d) Mass to be lifted $= \ 10\ \times 10^{2}kg$
[$\therefore$ density of water $= \ 10^{3}kgm^{- 3}$]
Height, $h = 10\ m$
Work done $= \ 10^{4} \times 10 \times 10 = 10^{6}J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.