Q. A rifle bullet loses $1/20^{th}$ of its velocity in passing through a plank. The least number of such planks required just to stop the bullet is

A) 5
B) 10
C) 11
D) 20
Explanation

(c) Let the thickness of one plank be $s$
[image:6_image51.png]
If bullet enters with velocity $u$ then it leaves with velocity
$v = \left( u - \frac{u}{20} \right) = \frac{19}{20}u$
From $v^{2} = u^{2} - 2as$
$\Rightarrow \left( \frac{19}{20}u \right)^{2} = u^{2} - 2as \Rightarrow \frac{400}{39} = \frac{u^{2}}{2as}$
Now if the $n$ planks are arranged just to stop the bullet then again from
$v^{2} = u^{2} - 2as$
[image:6_image52.png]
$0 = u^{2} - 2ans$
$\Rightarrow n = \frac{u^{2}}{2as} = \frac{400}{39}$
$\Rightarrow n = 10.25$
As the planks are more than 10 so we can consider $n = 11$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.