(b) Let the initial mass of body $= m$
Initial linear momentum $= mv$ …(i)
When it breaks into equal masses then one of the fragment retrace back with same velocity
$\therefore$ Final linear momentum $= \frac{m}{2}( - v) + \frac{m}{2}(v_{2})$ …(ii)
By the conservation of linear momentum
$\Rightarrow mv = \frac{- mv}{2} + \frac{mv_{2}}{2}$
$\Rightarrow v_{2} = 3v$
$i.e$., other fragment moves with velocity $3v$ in forward direction