Q. Two spheres $A$ and $B$ of masses $m_{1}$and $m_{2}$ respectively collide. $A$ is at rest initially and $B$ is moving with velocity $v$ along $x$-axis. After collision $B$ has a velocity $\frac{V}{2}$ in a direction perpendicular to the original direction. The mass $A$ moves after collision in the direction
A) Same as that of $B$
B) Opposite to that of $B$
C) $\theta = \tan^{- 1}{(1/2)}$ to the $x$-axis
D) $\theta = \tan^{- 1}{( - 1/2)}$ to the $x$-axis
Explanation
(d) [image:6_image53.emf]
Conservation of linear momentum along $x$-direction
$m_{2}v = m_{1}v_{x}$
$\frac{m_{2}v}{m_{1}} = v_{x}$
Along $y$ direction
$m_{2} \times \frac{v}{2} = m_{1}v_{y}$
$\tan\theta = \frac{1}{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.