If we throw a body upwards with velocity of $4\ m/s$, at what height does its kinetic energy reduce to half of the initial value (Taking $g = 10\ ms^{- 1}$)

Question

Dr. Abubacker · Accepted Answer

(d) At a given height the half of the kinetic energy of the body is equal to its potential energy.
Initial kinetic energy of the body
$= \frac{1}{2}mv^{2} = \frac{1}{2}m(4)^{2} = 8m$
Let at height $h$, the kinetic energy reduces to half, $i.e.,$ it becomes $4\ m$. It is also equal to potential energy.
Hence, $mgh = 4m$ or $h = \frac{4}{g} = \frac{4}{10} = 0.4\ m$

Q. If we throw a body upwards with velocity of $4\ m/s$, at what height does its kinetic energy reduce to half of the initial value (Taking $g = 10\ ms^{- 1}$)

Explanation

Reviewed by Dr. Abubacker

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