Q. Two springs of spring constants $1500\ N/m$ and $3000\ N/m$ respectively are stretched with the same force. They will have potential energy in the ratio
A) $4\ :1$
B) $1\ :4$
C) $2\ :1$
D) $1\ :2$
Explanation
(c) $U = \frac{F^{2}}{2k} \Rightarrow \frac{U_{1}}{U_{2}} = \frac{k_{2}}{k_{1}}$ [If force are same]
$\therefore\frac{U_{1}}{U_{2}} = \frac{3000}{1500} = \frac{2}{1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.