Q. If the momentum of a body is increased by 100%, then the percentage increase in the kinetic energy is
A) 150%
B) 200%
C) 225%
D) 300%
Explanation
(d) $E = \frac{P^{2}}{2m} \Rightarrow E_{2} = E_{1}\left( \frac{P_{2}}{P_{1}} \right)^{2} = E_{1}\left( \frac{2P}{P} \right)^{2}$
$\Rightarrow E_{2} = 4E_{1} = E_{1} + 3E_{1} = E + 300\%$ of $E$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.