(b) From force diagram as shown in figure
$mg - T = ma$
[image:6_image57.emf]
$T = mg - ma = mg - \frac{mg}{4} = \frac{3mg}{4}$
$\therefore\ W_{T} =$ work done by tension
$= \overrightarrow{\mathbf{T}}.\overrightarrow{\mathbf{s}} = Ts\cos{180{^\circ}} = - \frac{3mgd}{4}$