Q. A ball is dropped from a height $h$ on a floor of coefficient of restitution $e$.The total distance covered by the ball just before second hit is
A) $h(1 - 2e^{2})$
B) $h(1 + 2e^{2})$
C) $h(1 + e^{2})$
D) $he^{2}$
Explanation
(b) [image:6_image58.emf]
Total distance travelled by the ball before its second hit is
$H = h + 2h_{1}$
$= h\left\lbrack 1 + 2e^{2} \right\rbrack\ \ \ \ \ \ \ \ \ \ \ \ \ (\because h_{1} = he^{2})$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.