Power supplied to a particle of mass 2 kg varies with time as $P = \frac{3t^{2}}{2}$ watt. Here $t$ is in second. If the velocity of particle at $t = 0$ is $v = 0$, the velocity of particle at time $t = 2$ s will be

Question

Dr. Abubacker · Accepted Answer

(c) From work-energy theorem
$\mathrm{\Delta}\ KE\  = W_{net}$
or $K_{f} - K_{i} = \int_{}^{}{Pd}$
or $\frac{1}{2}mv^{2} = \int_{0}^{2}{\left( \frac{3}{2}t^{2} \right)dt}$
$v^{2} = \left\lbrack \frac{t^{3}}{2} \right\rbrack_{0}^{2}$
$v = 2\ ms^{- 1}$

Q. Power supplied to a particle of mass 2 kg varies with time as $P = \frac{3t^{2}}{2}$ watt. Here $t$ is in second. If the velocity of particle at $t = 0$ is $v = 0$, the velocity of particle at time $t = 2$ s will be

Explanation

Reviewed by Dr. Abubacker

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