Q. The blocks of mass $m$ each are connected to a spring of spring constant $k$ as shown in figure. The maximum displacement in the block is
A) $\sqrt{\frac{2mv^{2}}{k}}$
B) $\sqrt{\frac{mv^{2}}{k}}$
C) $2\sqrt{\frac{mv^{2}}{k}}$
D) $2\sqrt{\frac{k}{mv^{2}}}$
Explanation
(a) $\frac{1}{2}kx^{2} = \frac{1}{2}mv^{2} + \frac{1}{2}mv^{2} = mv^{2}$
$x = \sqrt{\frac{2mv^{2}}{k}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.