Q. A body constrained to move in the y-direction is subjected to force $\mathbf{F =}2\widehat{\mathbf{i}}\mathbf{+}15\widehat{\mathbf{j}}\mathbf{+}6\widehat{\mathbf{k}}$ N. The work done by this force in moving the body through a distance of 10 m along y-axis is

A) 100 J
B) 150 J
C) 120 J
D) 200 J
Explanation

(b) Force F=$(2\widehat{I}$+15$\widehat{j}$+6$\widehat{k}$)$N$
$Displacement\ s = 10\widehat{j}$m
$W =$F$\bullet s$=$(2\widehat{I}$+15$\widehat{j}$+6$\widehat{k}$)$\bullet (10\widehat{j}) = 150J$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.