Q. Stopping distance of a moving vehicle is directly proportional to
A) Square of the initial velocity
B) Square of the initial acceleration
C) The initial velocity
D) The initial acceleration
Explanation
(a) Let $d_{s}$ be the distance travelled by the vehicle before it stops
Here, final velocity $v = 0$, initial velocity $= u$
Using equation of motion $v^{2} = u^{2} + 2aS$
$\therefore 0^{2} = u^{2} + 2ad_{s}$
Or Stopping distance, $d_{s} = - \frac{u^{2}}{2a}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.